equations.md 403 B
{\displaystyle P(k{\text{ events in interval}})=e^{-\lambda }{\frac {\lambda ^{k}}{k!}}}
\frac{1 \text{ meteor}}{15 \text{ minutes}} * 60 \text{ minutes} = 4 \text{ meteors expected} = \lambda
{\displaystyle P(4{\text{ meteors in 1 hour}})=e^{-4}{\frac {4^{4}}{4!}}} = 0.195 = 19.5\%
P(T > t) = e^{-\text{rate} * {t}}
P(T \le t) = 1 - e^{-\text{rate} * {t}}
\Pr(X=k)={\binom {n}{k}}p^{k}(1-p)^{n-k}