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- # Copyright (c) 2017-present, Facebook, Inc.
- # All rights reserved.
- #
- # This source code is licensed under the BSD-style license found in the
- # LICENSE file in the root directory of this source tree. An additional grant
- # of patent rights can be found in the PATENTS file in the same directory.
- from __future__ import absolute_import
- from __future__ import division
- from __future__ import print_function
- from __future__ import unicode_literals
- import numpy as np
- import pandas as pd
- # fb-block 1 start
- import os
- from unittest import TestCase
- from fbprophet import Prophet
- from fbprophet import diagnostics
- DATA = pd.read_csv(
- os.path.join(os.path.dirname(__file__), 'data.csv'), parse_dates=['ds']
- ).head(100)
- # fb-block 1 end
- # fb-block 2
- class TestDiagnostics(TestCase):
- def __init__(self, *args, **kwargs):
- super(TestDiagnostics, self).__init__(*args, **kwargs)
- # Use first 100 record in data.csv
- self.__df = DATA
- def test_simulated_historical_forecasts(self):
- m = Prophet()
- m.fit(self.__df)
- k = 2
- for p in [1, 10]:
- for h in [1, 3]:
- period = '{} days'.format(p)
- horizon = '{} days'.format(h)
- df_shf = diagnostics.simulated_historical_forecasts(
- m, horizon=horizon, k=k, period=period)
- # All cutoff dates should be less than ds dates
- self.assertTrue((df_shf['cutoff'] < df_shf['ds']).all())
- # The unique size of output cutoff should be equal to 'k'
- self.assertEqual(len(np.unique(df_shf['cutoff'])), k)
- self.assertEqual(
- max(df_shf['ds'] - df_shf['cutoff']),
- pd.Timedelta(horizon),
- )
- dc = df_shf['cutoff'].diff()
- dc = dc[dc > pd.Timedelta(0)].min()
- self.assertTrue(dc >= pd.Timedelta(period))
- # Each y in df_shf and self.__df with same ds should be equal
- df_merged = pd.merge(df_shf, self.__df, 'left', on='ds')
- self.assertAlmostEqual(
- np.sum((df_merged['y_x'] - df_merged['y_y']) ** 2), 0.0)
- def test_simulated_historical_forecasts_logistic(self):
- m = Prophet(growth='logistic')
- df = self.__df.copy()
- df['cap'] = 40
- m.fit(df)
- df_shf = diagnostics.simulated_historical_forecasts(
- m, horizon='3 days', k=2, period='3 days')
- # All cutoff dates should be less than ds dates
- self.assertTrue((df_shf['cutoff'] < df_shf['ds']).all())
- # The unique size of output cutoff should be equal to 'k'
- self.assertEqual(len(np.unique(df_shf['cutoff'])), 2)
- # Each y in df_shf and self.__df with same ds should be equal
- df_merged = pd.merge(df_shf, df, 'left', on='ds')
- self.assertAlmostEqual(
- np.sum((df_merged['y_x'] - df_merged['y_y']) ** 2), 0.0)
- def test_simulated_historical_forecasts_default_value_check(self):
- m = Prophet()
- m.fit(self.__df)
- # Default value of period should be equal to 0.5 * horizon
- df_shf1 = diagnostics.simulated_historical_forecasts(
- m, horizon='10 days', k=1)
- df_shf2 = diagnostics.simulated_historical_forecasts(
- m, horizon='10 days', k=1, period='5 days')
- self.assertAlmostEqual(
- ((df_shf1['y'] - df_shf2['y']) ** 2).sum(), 0.0)
- self.assertAlmostEqual(
- ((df_shf1['yhat'] - df_shf2['yhat']) ** 2).sum(), 0.0)
- def test_cross_validation(self):
- m = Prophet()
- m.fit(self.__df)
- # Calculate the number of cutoff points(k)
- horizon = pd.Timedelta('4 days')
- period = pd.Timedelta('10 days')
- k = 5
- df_cv = diagnostics.cross_validation(
- m, horizon='4 days', period='10 days', initial='90 days')
- # The unique size of output cutoff should be equal to 'k'
- self.assertEqual(len(np.unique(df_cv['cutoff'])), k)
- self.assertEqual(max(df_cv['ds'] - df_cv['cutoff']), horizon)
- dc = df_cv['cutoff'].diff()
- dc = dc[dc > pd.Timedelta(0)].min()
- self.assertTrue(dc >= period)
- def test_cross_validation_default_value_check(self):
- m = Prophet()
- m.fit(self.__df)
- # Default value of initial should be equal to 3 * horizon
- df_cv1 = diagnostics.cross_validation(
- m, horizon='32 days', period='10 days')
- df_cv2 = diagnostics.cross_validation(
- m, horizon='32 days', period='10 days', initial='96 days')
- self.assertAlmostEqual(
- ((df_cv1['y'] - df_cv2['y']) ** 2).sum(), 0.0)
- self.assertAlmostEqual(
- ((df_cv1['yhat'] - df_cv2['yhat']) ** 2).sum(), 0.0)
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