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Not an alternative, but introductory work

This was not intended to be an alternative, but for explanation on how to begin such a query. This one only returns all required friendships including those already existing.

Then better delete it completely.
Stefan Koch 12 년 전
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1개의 변경된 파일0개의 추가작업 그리고 5개의 파일을 삭제
  1. 0 5
      documents/musterloesung-db-2012-09-24/d2c1.2.sql

+ 0 - 5
documents/musterloesung-db-2012-09-24/d2c1.2.sql

@@ -1,5 +0,0 @@
-SELECT f1.person2, f2.person2 
-    FROM FriendshipSymmetric f1
-    JOIN FriendshipSymmetric f2 ON f1.person1 = f2.person1
-    WHERE f1.person2 != f2.person2
-        AND f1.person1 = <id>;