longest_common_subsequence.py 2.1 KB

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  1. # Copyright (c) 2018 luozhouyang
  2. #
  3. # Permission is hereby granted, free of charge, to any person obtaining a copy
  4. # of this software and associated documentation files (the "Software"), to deal
  5. # in the Software without restriction, including without limitation the rights
  6. # to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
  7. # copies of the Software, and to permit persons to whom the Software is
  8. # furnished to do so, subject to the following conditions:
  9. #
  10. # The above copyright notice and this permission notice shall be included in all
  11. # copies or substantial portions of the Software.
  12. #
  13. # THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
  14. # IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
  15. # FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
  16. # AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
  17. # LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
  18. # OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
  19. # SOFTWARE.
  20. import numpy as np
  21. from .string_distance import StringDistance
  22. class LongestCommonSubsequence(StringDistance):
  23. def distance(self, s0, s1):
  24. if s0 is None:
  25. raise TypeError("Argument s0 is NoneType.")
  26. if s1 is None:
  27. raise TypeError("Argument s1 is NoneType.")
  28. if s0 == s1:
  29. return 0.0
  30. return len(s0) + len(s1) - 2 * self.length(s0, s1)
  31. @staticmethod
  32. def length(s0, s1):
  33. if s0 is None:
  34. raise TypeError("Argument s0 is NoneType.")
  35. if s1 is None:
  36. raise TypeError("Argument s1 is NoneType.")
  37. s0_len, s1_len = len(s0), len(s1)
  38. x, y = s0[:], s1[:]
  39. n, m = s0_len + 1, s1_len + 1
  40. matrix = np.zeros((n, m))
  41. for i in range(1, s0_len + 1):
  42. for j in range(1, s1_len + 1):
  43. if x[i - 1] == y[j - 1]:
  44. matrix[i][j] = matrix[i - 1][j - 1] + 1
  45. else:
  46. matrix[i][j] = max(matrix[i][j - 1], matrix[i - 1][j])
  47. return matrix[s0_len][s1_len]